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ajwin

(Big box area - small box area)/4 So (60x60 - 48x48)/4


ajwin

You could also do avg length of top and bottom side of the trapeze x height so (60+48)/2 x 6


Kimy_tel

thank You so much for providing 2 ways(of solving) that check out!


Kimy_tel

Omg… this is so simple and makes so much sense and I didn’t even think of it 😭. Thanks so much!


Desperate-Chipmunk76

>It also says that the distance between the 2 squares is 6 cm. Edge-to-edge or corner-to-corner distance?


Kimy_tel

Edge to edge. It doesn’t say about corner to corner


Desperate-Chipmunk76

Alright......so the area of big square is 60×60=3600 cm^2. Smaller square has length 60–12 = 48 cm so area = 2304 cm^2. Difference between the larger and the smaller square is the area of four trapeziums. So the area of one trapezium is (3600 –2304)/4 = 324 cm2.


st3f-ping

You have the length of one of the parallel sides and the height. Can you find the length of the other parallel side?