## Help this poor soul out with a geometry problem.

The image should look like this: 1 big square with a smaller one inside it. The corners of the 2 squares are connected with one line each, forming 4 trapezes. The height of the big square is 60 cm, basically one side is 60 cm long. It also says that the distance between the 2 squares is 6 cm (edge to edge). Calculate the area of one trapeze. (It says to calculate the bottom one but I don’t think it makes a difference which one to calculate). Help pls T_T

Edit: there’s a photo if someone doesn’t understand how the problem should look like. https://imgur.com/a/Hc53XUW

(Big box area - small box area)/4 So (60x60 - 48x48)/4

You could also do avg length of top and bottom side of the trapeze x height so (60+48)/2 x 6

thank You so much for providing 2 ways(of solving) that check out!

Omg… this is so simple and makes so much sense and I didn’t even think of it 😭. Thanks so much!

>It also says that the distance between the 2 squares is 6 cm. Edge-to-edge or corner-to-corner distance?

Edge to edge. It doesn’t say about corner to corner

Alright......so the area of big square is 60×60=3600 cm^2. Smaller square has length 60–12 = 48 cm so area = 2304 cm^2. Difference between the larger and the smaller square is the area of four trapeziums. So the area of one trapezium is (3600 –2304)/4 = 324 cm2.

You have the length of one of the parallel sides and the height. Can you find the length of the other parallel side?